Question

g Two point charges -6 C and -8 C charge are 12 cm apart. What is the magnitude of the electric field at a point half-way between the two charges

Answer 1

Explanation:

q1 = -6

q2 = -8

d^2 = (6/100)^2 = 0.0036

k = 1/4*(pi*E) where E js the permittivity of free space

F = (k*q1*q2)/(d^2)

Substitute your values into this equation and solve