Question

Particles 91, 92, and q3 are in a straight line.
Particles q1 = -28.1 uc, q2 = +25.5 uc, and
q3 = -47.9 uc. Particles qi and q2 are separated
by 0.300 m. Particles q2 and q3 are separated by
0.300 m. What is the net force on q3?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right

Answer 1

The net force on particle 3 due to the presence of particle 1 and particle 2 on the same straight line is 50.5 N to the right.

Force between particle 1 and particle 2

The force between the two particles is determined from Coulomb's law as shown below;

F = kq₁q₂/r²

F(1,2) = -(9 x 10⁹ x 28.1 x 10⁻⁶ x 25.5 x 10⁻⁶) / (0.3)²

F(1,2) = - 71.66 N

Force between particle 2 and particle 3

F(2,3) = + (9 x 10⁹ x 25.5 x 10⁻⁶ x 47.9 x 10⁻⁶) / (0.3)²

F(2,3) = + 122.15 N

Net force on particle 3

The net force on particle 3 is determined as follows;

F(net) = 122.15 N - 71.66 N

F(net) = + 50.5 N

Thus, the net force on particle 3 due to the presence of particle 1 and particle 2 on the same straight line is 50.5 N to the right.

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