Respuesta :

The minimum amount of NaOH and HCl that must be present to produce 18.48grams of NaCl is 12.6g and 11.5g  respectively.

Calculation of amount of reactants

The balanced neutralization reaction equation for the formation of NaCl is,

NaOH + HCl ---> NaCl + H2

The molar mass of NaOH = 23+16+1 = 40g/mol

The molar mass of NaCl = 23 +35.5 = 58.5g/mol

If  40g of NaOH = 58.5g of NaCl

∴ x g of NaOH   = 18.48g of NaCl

Make xg the subject of formula,

x g of NaOH = 40 × 18.48/58.5

                     = 739.2/58.5

                     = 12.6g of NaOH

The molar mass of HCl = 1 +35.5 = 36.5g/mol

If  36.5g of  HCl= 58.5g of NaCl

∴ x g   of HCl       = 18.48g of NaCl

Make xg the subject of formula,

x g of HCl       = 36.5 × 18.48/58.5

                       = 674.52/58.5

                       = 11.5g of HCl

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