The minimum amount of NaOH and HCl that must be present to produce 18.48grams of NaCl is 12.6g and 11.5g respectively.
The balanced neutralization reaction equation for the formation of NaCl is,
NaOH + HCl ---> NaCl + H2
The molar mass of NaOH = 23+16+1 = 40g/mol
The molar mass of NaCl = 23 +35.5 = 58.5g/mol
If 40g of NaOH = 58.5g of NaCl
∴ x g of NaOH = 18.48g of NaCl
Make xg the subject of formula,
x g of NaOH = 40 × 18.48/58.5
= 739.2/58.5
= 12.6g of NaOH
The molar mass of HCl = 1 +35.5 = 36.5g/mol
If 36.5g of HCl= 58.5g of NaCl
∴ x g of HCl = 18.48g of NaCl
Make xg the subject of formula,
x g of HCl = 36.5 × 18.48/58.5
= 674.52/58.5
= 11.5g of HCl
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