A 1.2-kg mass is oscillating without friction on a spring whose spring constant is 3400 N/m. When the mass's displacement is 7.2 cm, what is its maximum acceleration

Respuesta :

The maximum acceleration of the mass oscillating on the spring whose spring constant is 3400 N/m, is determined as 204 m/s².

Applied force on the spring

The force applied on the spring to cause the mass to displace to the given distance is determined by applying Hooke's law;

F = kx

F = (3400 N/m) x (0.072 m)

F = 244.8 N

Maximum acceleration

The maximum acceleration of the mass is determined from Newton's second law of motion as shown below;

F = ma

a = F/m

a = 244.8 / 1.2

a = 204 m/s²

Learn more about acceleration here: https://brainly.com/question/14344386

ACCESS MORE