Matt went on a bike ride of 60 miles. He realized that if he had gone 6 mph faster, he would have arrived 5 hours sooner. How fast did he actually ride

Respuesta :

Matt travelled on a bike and cover a distance of 60 miles . If he had gone 6mph faster, he would have arrived 5 hours. Therefore, the actual rate  is 6 mph.

What is rate?

Rate is the ratio between two related quantities in different units.

He went on a bike ride of 60 miles.

He realized if he had gone 6 miles per hour he would have arrived 5 hours earlier.

The speed he actually ride can be calculated as follows:

let

x = speed he actually ride

y = time he arrived

Therefore,

speed = distance / time

x = 60 / y

On, the other hand his permutation is as follows:

x + 6 = 60 / y - 5

(x + 6)(y - 5) = 60

since, x = 60 / y we can substitute it in the equation

(60 / y + 6)(y - 5) = 60

60 - 300 / y + 6y - 30 = 60

- 300 / y + 6y = 60 - 30

- 300 / y + 6y = 30

6y² - 300 = 30y

6y² - 30y - 300 = 0

y² - 5y - 50 = 0

y² + 5y - 10y - 50 = 0

y(y + 5) -10(y + 5) = 0

(y - 10)(y + 5) = 0

y = 10 or -5

we cannot use negative values.

Therefore,

y = 10

x = 60 / y = 60 / 10 = 6 miles per hour

He actually rode 6 miles per hour.

If he went 6 mph faster that would be 6+6 = 12 mph

If he arrived 5 hrs sooner that would be 10 - 5 = 5 hrs

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