The standard deviation of the dataset is the square root of the variance
The mean and the standard deviation of the dataset are 24.6 and 5.70, respectively
The dataset is given as;
25, 24, 32, 16, 22, 34. 19. 27, 18, 29
Calculate the mean using:
μ = Sum/Count
So, we have:
μ = (25+ 24+ 32+ 16+ 22+ 34+ 19+ 27+ 18+ 29)/10
Evaluate
μ = 24.6
The standard deviation is then calculated using:
[tex]\sigma =\sqrt{ \frac{\sum(x - \mu)^2}{n}[/tex]
So, we have:
[tex]\sigma = \sqrt{\frac{(25 - 24.6)^2 + .................. + (27- 24.6)^2 + (18- 24.6)^2 + (29- 24.6)^2}{10}}[/tex]
Evaluate
[tex]\sigma = \sqrt{32.44}[/tex]
Evaluate the square root
[tex]\sigma = 5.70[/tex]
Hence, the mean and the standard deviation of the dataset are 24.6 and 5.70, respectively
Read more about variance at:
https://brainly.com/question/15858152