An erect object is 50 cm from a concave mirror of radius 60 cm. In the situation above, the object is moved to a new position, such that the new lateral magnification is 2.5. The new object distance, in cm, is closest to:

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19-04-2022
Physics

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An erect object is 50 cm from a concave mirror of radius 60 cm. In the situation above, the object is moved to a new position, such that the new lateral magnification is 2.5. The new object distance, in cm, is closest to:

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okpalawalter8 okpalawalter8 · Answer 1 · 2022-04-27T11:47:53+02:00

For an erect object is 50 cm from a concave mirror of radius 60 cm. In the situation above, the object is moved to a new position, the new object distance is mathematically given as

u = -18cm

What is the new object distance?

Generally, the equation for magnification is mathematically given as

1/f = 1/v +1/u

therefore,

-1/30 = 1/v + 1/u

v = -2.5u

Hence,

-1/30 = -1/2.5u + 1/u

-1/30 = (3/5)u

u = -18

In conclusion, the new object distance is

u = -18cm