Question

Mr. Alexander was traveling home from a business
trip. A taxi driver took him from his hotel room to a
bus station that was 18 miles away. The taxi traveled at an average rate of 60 miles an hour.
Mr. Alexander waited 15 minutes at the bus station
before leaving on a 178-mile bus ride.
Mr. Alexander's trip took a total of 5 hours from the time he left the hotel to the time the bus arrived at its destination. At
what average rate did the bus travel? Explain or show calculations to support the answer.

Answer 1

Using the relation between velocity, distance and time, it is found that the bus traveled at a rate of 40 miles per hour.

What is the relation between velocity, distance and time?

Velocity is distance divided by time, that is:

$v = \frac{d}{t}$

The taxi took 18 minutes(60 miles per hour = 1 mile per minute), while he waited for 15 minutes at the station. Thus, the 178-mile bus trip took 4 hours and 27 minutes, so t is given by:

$t = 4 + \frac{27}{60} = 4.45$

Hence, the velocity is given by:

$v = \frac{d}{t} = \frac{178}{4.45} = 40$

The bus traveled at a rate of 40 miles per hour.

More can be learned about the relation between velocity, distance and time at https://brainly.com/question/24316569