Suppose a line, with a slope of -3 and a y-intercept of 4, is translated -4 units along the x-axis and 6 units along the y-axis. What is the equation of this new line?

Respuesta :

Answer:

[tex]y=-3x-2[/tex]

Step-by-step explanation:

Slope-intercept form of a linear equation:  [tex]y=mx+b[/tex]

where:

  • [tex]m[/tex] is the slope
  • [tex]b[/tex] is the y-intercept

Given:

  • slope (m) = -3
  • y-intercept (b) = 4

Equation of line: [tex]y=-3x+4[/tex]

If the line is translated -4 units along the axis, we need to substitute

[tex]x \rightarrow (x+4)[/tex]

If the line is translated 6 units along the y-axis, we need to add 6 to the equation:

[tex]\implies y=-3(x+4)+4+6[/tex]

[tex]\implies y=-3(x+4)+10[/tex]

[tex]\implies y=-3x-12+10[/tex]

[tex]\implies y=-3x-2[/tex]

Answer:

y = -3x - 2

Step-by-step explanation:

Rules to remember :

  • f(x + a) = translated 'a' units left
  • f(x - a) = translated 'a' units right

Standard form of the original equation

  • y = mx + b
  • here m = slope and b = y-intercept
  • y = -3x + 4

Translating -4 units along the x-axis

  • y = -3(x + 4) + 4
  • y = -3x - 12 + 4
  • y = -3x - 8

Translating 6 units along the y-axis

  • y = -3x - 8 + 6
  • y = -3x - 2
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