Question

For PQR, which one is equal to sin(P)?

Answer 1

Answer:

The third option.

$cos(Q)=\frac{RQ}{PQ}$  

Step-by-step explanation:

SIN is opposite over hypotenuse.

COS is adjacent over hypotenuse

Therefore

$sin(P)=\frac{RQ}{PQ}$

Then we have 4 options.

It is not the first option beacause we can't determine which side is adjacent to the angle.

The second option

$sin(Q)=\frac{RP}{QP}$

The third option

$cos(Q)=\frac{RQ}{PQ}$

It is not the fourth option beacause we can't determine which side is opposite to the angle.

Finally we see that

$cos(Q)=\frac{RQ}{PQ}$  

and

$sin(P)=\frac{RQ}{PQ}$

are equivalent.