Question

The partial pressures of gases A, B, and C in a mixture are
0.75 atmosphere, 0.25 atmosphere, and 1.25 atmospheres,
respectively. What is the total pressure of the gas mixture
in millimeters of Hg?
A. 1710 mm of Hg
B.
1140 mm of Hg
C. 760.0 mm of Hg
D. 570.0 mm of Hg

Answer 1

Answer:

A

Explanation:

.75 + .25 + 1.25 = 2.25 atm

1 atm is 760 mm hg

2.25 * 760 = 1710 mm HG

Answer 2

Answer:

$\huge\boxed{\sf 2.25\ atm = 1710\ mm\ of\ Hg}$

Explanation:

Partial pressure of gas A = 0.75 atm

Partial pressure of gas B = 0.25 atm

Partial pressure of gas C = 1.25 atm

Total partial pressure = 0.75 atm + 0.25 atm + 1.25 atm

= 2.25 atm

We know that:

1 atm = 760 mm of Hg

Multiply 2.25 to both sides

2.25 atm  = 760 × 2.25 mm of Hg

2.25 atm = 1710 mm of Hg

$\rule[225]{225}{2}$