Question

A loudspeaker diaphragm is oscillating in simple harmonic motion with a frequency of 379 Hz and a maximum displacement of 0.562 mm. What are the (a) angular frequency, (b) maximum speed, and (c) magnitude of the maximum acceleration

Answer 1

Answer:

f = 379 / s          given

A)     ω = 2 pi f = 2380 / sec

B)   Vmax = ω A = 2380 / sec * .000562 m = 1.34 m.s

C)   amax = -ω^2 A = -(2380)^2 * .000562 = -3180 m/s^2