Considering the area of the rectangle, it is found that it's width of the rectangle is of 3 inches.
The area of a rectangle of length l and width w is given by:
A = lw.
In this problem, we have that:
A = 108, l = 6 + 4w.
Hence, using the equation for the area:
lw = 108
(6 + 4w)w = 108
4w² + 6w - 108 = 0
2w² + 3w - 54 = 0
Which is a quadratic equation with coefficients a = 2, b = 3 and c = -54, hence:
[tex]\Delta = b^2 - 4ac = (3)^2 - 4(2)(-54) = 441[/tex]
[tex]x_1 = \frac{-3 + \sqrt{441}}{6} = 3[/tex]
[tex]x_2 = \frac{-3 - \sqrt{441}}{6} = -4[/tex]
Width is a positive measure, hence it is of 3 inches.
More can be learned about the area of a rectangle at https://brainly.com/question/10489198