Question

solve for a ~
$a {}^{2} - 5a + 6 = 0$

thankyou ~​

Answer 1

Answer:

Hi there!

Given equation :-

$\:\mathsf{a^2\:-\:5a\:+\:6\:=\:0}$

Now

=> By splitting the middle term

=> $\:\mathsf{a^2\:-\:2a\:-\:3a\:+\:6\:=\:0}$

=> $\:\mathsf{a(a\:-\:2)\:-\:3(a\:-\:2)\:=\:0}$

=> $\:\mathsf{(a\:-\:2)\:-\:(a\:-\:3)\:=\:0}$

We get ,

=> $\:\sf{a\:=\:2\: and\: a\:=\:3}$

$\:\mathsf{Hope\:this\:helps\:you!\::)}$

Thank you!

Answer 2

Answer:

$a = 3 \: \: \: and \: \: a = 2$

Step-by-step explanation:

⬇

$a^{2} - 3a - 2a + 6 = 0$

⬇

$a \: (a - 3) \: \: (a - 2)$

⬇

${}\ a - 3 = 0 \\ a = 2{}$