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What are the solutions of x2 = 8 – 5x? startfraction 5 minus startroot 57 endroot over 2 endfraction comma startfraction 5 + startroot 57 endroot over 2 endfraction startfraction negative 5 minus startroot 57 endroot over 2 endfraction comma startfraction negative 5 + startroot 57 endroot over 2 endfraction startfraction negative 47 over 4 endfraction comma startfraction 67 over 4 endfraction startfraction negative 67 over 4 endfraction comma startfraction 47 over 4 endfraction

Respuesta :

The solution of the equation x² = 8 - 5x is startfraction negative 5 minus startroot 57 endroot over 2 endfraction comma startfraction negative 5 + startroot 57 endroot over 2 endfraction

How to solve quadratic equation?

x² = 8 - 5x

x² + 5x - 8 = 0

Using quadratic formula

x = -b ± √b² - 4ac / 2a

= -5 ± √5² - 4(1)(-8) / 2(1)

= -5 ± √25 -(-32) / 2

= -5 ± √25 + 32 / 2

= -5 ± √57 / 2

= -5 + √57 /2 or -5 -√57/2

Therefore, the correct answer is; startfraction negative 5 minus startroot 57 endroot over 2 endfraction comma startfraction negative 5 + startroot 57 endroot over 2 endfraction

-5 - √57 / 2, -5 + √57 / 2

Learn more about quadratic equation:

https://brainly.com/question/1214333

Answer:

B)

Image to help is below here, sorry if its bad quality but good luck <3

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