Using the normal distribution, it is found that 0.1056 = 10.56% of runners do not earn the competition medal.
The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
In this problem, considering the 4.5 additional minutes, the mean and the standard deviation are given, respectively, by:
[tex]\mu = 22.5, \sigma = 2[/tex].
Runners that take more than 25 minutes to complete the race do not earn a medal, hence the proportion is one subtracted by the p-value of Z when X = 25, so:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{25 - 22.5}{2}[/tex]
Z = 1.25
Z = 1.25 has a p-value of 0.8944.
1 - 0.8944 = 0.1056.
0.1056 = 10.56% of runners do not earn the competition medal.
More can be learned about the normal distribution at https://brainly.com/question/24663213