Question

A heat engine exhausts 6000 J of heat while performing 2000 J of useful work.
Determine the efficiency of the engine

Answer 1

Answer:

Explanation:

The efficiency can be calculated by:

$\eta = \frac{Q_{E}-Q_{W}}{Q_{E}}=\frac{6000-2000}{6000}=\frac{2}{3}$

or we can say it becomes approximately 66.7%