Answer:
a^1/12 or choice A
Step-by-step explanation:
Given:
[tex]\displaystyle \large{\dfrac{a^{\dfrac{1}{3}}}{a^{\dfrac{1}{4}}}}[/tex]
Law of Exponent (Division Property):
[tex]\displaystyle \large{\dfrac{a^m}{a^n} = a^{m-n}}[/tex]
Therefore:
[tex]\displaystyle \large{a^{\dfrac{1}{3}-\dfrac{1}{4}}}[/tex]
Then evaluate the fractions. Keep in mind that we can only evaluate fractions with same denominator. Therefore, calculate the LCM of 3,4 which is 12:
[tex]\displaystyle \large{a^{\dfrac{4}{12}-\dfrac{3}{12}} = a^{\dfrac{1}{12}}}[/tex]
Therefore, the solution is a^1/12 or choice A