Question

Last one, I promise!!! ._.

19x+28=20x-53

Answer 1

Answer:

x = 81

Step-by-step explanation:

Given:

$\displaystyle \large{19x+28=20x-53}$

Subtract both sides by 28:

$\displaystyle \large{19x+28-28=20x-53-28}\\\displaystyle \large{19x=20x-81}$

Subtract both sides by 19x:

$\displaystyle \large{19x-19x=20x-81-19x}\\\displaystyle \large{0=x-81}$

Add both sides by 81:

$\displaystyle \large{0+81=x-81+81}\\\displaystyle \large{81=x}\\\displaystyle \large{\therefore x=81}$

Therefore, the solution is x = 81

Let me know if you have any questions!

Answer 2

${\boxed{\mathfrak{✿ฺSolution :}}}$

$\bold{ 19x+28 = 20 x - 53 }$

$\bold{ 19x+28 - 28 =20x - 53 - 28}$

$\bold{ 19x = 20x - 81 }$

$\bold{ 19x - 20x = 20x - 81 - 20x }$

$\bold{ -x = - 81 }$

$\bold{ \frac{ - x}{ - 1} = \frac{ - 81}{ - 1} }$

$\bold{ x = 81 }$