Answer:
The missing value is 6a
Step-by-step explanation:
Given:
[tex]\displaystyle \large{A(-3a,b)}\\\displaystyle \large{B(3a,b)}[/tex]
Find:
Missing Value
Distance Formula:
[tex]\displaystyle \large{\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}[/tex]
Determine:
[tex]\displaystyle \large{(x_2,y_2)=(3a,b)}\\\displaystyle \large{(x_1,y_1)=(-3a,b)}[/tex]
Input given information above in the formula:
[tex]\displaystyle \large{AB=\sqrt{(3a-(-3a))^2+(b-b)^2}}\\\displaystyle \large{AB=\sqrt{(3a+3a)^2+(0)^2}}\\\displaystyle \large{AB=\sqrt{(6a)^2}}\\\displaystyle \large{AB=6a}[/tex]
The length is 6a but since we want to find the value in the square root then the answer is still 6a