Question

For the curve y=x^4+1, find the gradient of the secant between the point (1, 2) and
the point where x=1.01.

Answer 1

Answer:

4.06.

Step-by-step explanation:

Where x = 1.01,  y = (1.01)^4 + 1 = 1.0406 + 1

= 2.0406

So the gradient between (1, 2) and (1.01, 2.0406)

= (2.0406 - 1)/(1.01 - 1)

= 4.06.