Question

Determine the ph of a 0. 188 m nh3 solution at 25°c. The kb of nh3 is 1. 76 × 10-5.

Answer 1

$\tt [OH^-]=\sqrt{Kb.M}$

[OH⁻]=√1.76.10⁻⁵.0.188

[OH⁻]=1.81 x 10⁻³

pOH = 3 - log 1.81

pH = 11 + log 1.81