A 1.50-L vessel is filled with helium at 25.0 °C and 3.04 atm. Under these conditions, the mass of helium is 0.744 g.
An ideal gas is that whose particles have negligible volume and intermolecular forces.
A 1.50 L vessel at 25.0 °C contains He at a pressure of 3.04 atm.
We will use the following expression.
K = °C + 273.15 = 25.0 + 273.15 = 298.2 K
We will use the ideal gas equation.
P × V = n × R × T
n = P × V / R × T
n = 3.04 atm × 1.50 L / (0.0821 atm.L/mol.K) × 298.2 K = 0.186 mol
The molar mass of He is 4.00 g/mol.
0.186 mol × 4.00 g/mol = 0.744 g
A 1.50-L vessel is filled with helium at 25.0 °C and 3.04 atm. Under these conditions, the mass of helium is 0.744 g.
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