Question

help me solve the following question below in the attachment

Answer 1

Answer:

Explanation:

The point P is influenced by two electric fields, that are from Q1 and Q2. Because Q1 is a positive point charge, the E-fields is going to the right and the E-fields from Q2 is going to the left because of negative point charge. So:

$E_{1}=\frac{kQ_{1}}{R_{1}^{2}}$

$E_{2}=\frac{kQ_{2}}{R_{2}^{2}}$

Where R1 = 2 + 3 = 5 m, and R2 = 3 m. With k = $k=9\times 10^{9}$ in $Nm^{2}/C^{2}$, we can obtain:

$E_{1}=(9\times 10^{9})\frac{500\times10^{-6}}{25}=180\times 10^{3}$ N/C (+)

$E_{2}=(9\times 10^{9})\frac{100\times 10^{-6}}{9}=100\times 10^{3}$ N/C (-)

So: the Electric Field at P : $E_{P}=E_{1}-E_{2}=(180-100)\times 10^{3}=8\times 10^{4}$ N/C in magnitude