Sodium hydroxide is a soluble strong base. The pOH of a 3.0 × 10⁻³ M-sodium hydroxide solution is 2.5.
According to Arrhenius, a base is a species that releases OH⁻ ions in an aqueous medium.
Let's consider the basic reaction of NaOH.
NaOH(s) ⇒ Na⁺(aq) + OH⁻(aq)
NaOH is a strong base. This means that the concentration of OH⁻ will be equal to the initial concentration of NaOH, i.e. 3.0 × 10⁻³ M.
Then, we can calculate the pOH of the NaOH solution using the following expression.
pOH = -log [OH⁻] = -log 3.0 × 10⁻³ = 2.5
Sodium hydroxide is a soluble strong base. The pOH of a 3.0 × 10⁻³ M-sodium hydroxide solution is 2.5.
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