Question

Given the following equation: NaOH + HCl -> NaCl + H2O. Calculate the mass of water produced when 80.0 g of NaOH react with excess HCl.

Answer 1

Answer:

36 grams

Explanation:

Na    22.989

O       15.999

H     1.008          total  39.996   gm per mole

80 grams    is    80 / 39.996 = ~ 2 moles

From the equation each mole of NaOH used results in ONE mole of H2O

   so you will get two moles of H20

       (1.008 *2 + 15.999)   * 2 =  ~ 36 gm