Question

Here are two squares, A and B.
B
The length of the side of square A is 50% of the length of the side of square B.
Express the area of the shaded region of square A
as a percentage of the area of square B.

Answer 1

Answer:

The shaded region of A is 12.5% of the area of B.

Step-by-step explanation:

Although the side of square A is 50% of the side of square B, if you think about things logically here square A is only 25%of square B. Therefore the shaded area HAS to be half of 25% making the answer 12.5%

Answer 2

{Hello, arman78624}

Answer:

12.5%

Step-by-step explanation:

Since it given that the length of the sie of a square A is 50% of the  length of the side of square B. As well as given us the question we need to find the answer to which is:

Express the area of the shaded region of square A as a percentage of the area of square B.

What we need:

Area of shaded region of Square A as a % of Area of Square B

Now we can solve but first :

Let "b" be the side length of Square B

Let "a" be the side length of Square A

As well as:

It given side length of Square A (a) = 50% (1/2) of side length of Square B (b), therefore we have,

a = ½b

Area of a square = s², where s is the  side length

Area of Square A = (½b)² = b²/4

Area of Square B = b²

Finding the area of the shaded region of the Square A = ½ of area of Square A.

Area of shaded region of Square A = ½*(b²/4) = b²/8

Expressing the area of the shaded portion of square A as a percentage of are of Square B:

Area of shaded portion of Square A ÷ Area of Square B × 100%

Solving:

⇒ $\frac{\frac{b^2}{8}}{b^2}\times100$

⇒$\frac{b^2}{8}\times\frac{1}{b^2}\times100$

⇒ $\frac{b^2\times1}{8\timesb^2}\times100$

⇒ $\frac{b^2}{8\times b^2}\times100$

⇒ $\frac{1}{8}\times100=12.5$

Base on the solving above we can conclude that:

The area of the shaded region of Square A is 12.5% of the area of Square B.

~[DiscordUser]~