Question

What volume of water is used to prepare a 3.5 M solution if 45 grams of Na2CO3 is used?

Answer 1

Answer:

121.3 ml

Explanation:

Mole wts

Na    22.989 x 2

C    12.011

O 15.999 x 3      total = 105.986

45 grams is   45/105.986 of a mole

    45/105.986  in one liter would be .424584 M

   .424585 mole / x liter = 3.5

   x = .1213 liter = 121.3 ml