The concentration of the HCl solution needed to neutralize 25 mL of 0.2 M NaOH is 0.25 M
Balanced equation
HCl + NaOH —> NaCl + H₂O
From the balanced equation above,
- The mole ratio of the acid, HCl (nA) = 1
- The mole ratio of the base, NaOH (nB) = 1
How to determine the concentration of HCl
- Volume of base, KOH (Vb) = 25 mL
- Concentration of base, NaOH (Cb) = 0.2 M
- Volume of acid, HCl (Va) = 20 mL
- Concentration of acid, HCl (Ca) =?
CaVa / CbVb = nA / nB
(Ca × 20) / (0.2 × 25) = 1
(Ca × 20) / 5 = 1
Cross multiply
Ca × 20 = 5
Divide both side by 20
Ca = 5 / 20
Ca = 0.25 M
Thus, the concentration of the HCl solution is 0. 25 M
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