Question

What is the value of x?
What is the value of y?

Answer 1

Answer:

Step-by-step explanation:

Use Pythagorean's theorem. The two shorter sides (6+x) and 20 are apart of a right triangles of a hypotenuse of (18+6). Therefore:

$(6+x)^2+20^2} =(18+6)^2$

$(6+x)^2+400 =576$

$(6+x)^2=176$

Take the square root of both sides:

$6+x=\sqrt{176}$

$x=\sqrt{176} -6$

Moving on to the smaller triangle, we can find the value of 'y' to be:

$6^2+y^2=18^2$

$y^2+36=324$

$y^2=288$

$y=\sqrt{288}$