Question #18:

A steam engine (assume a Carnot engine) has an efficiency of 34.8%. If the waste heat has a temperature of 76 °C, what is the temperature of the boiler? Answer in units of °C.

Respuesta :

The temperature of the boiler of the steam engine at the efficiency of 34.8% and waste heat temperature of 76 °C, is determined as 116.56°C.

Efficiency of a Carnot engine

The efficiency of a Carnot engine is determined using the following formula;

n = 100% x (TH - TC)/TH

where;

  • TH is the temperature of the hot reservoir
  • Tc is the temperature of the cold reservoir

34.8% =  100% x (TH - 76)/TH

0.348 = (TH - 76)/TH

0.348TH = TH - 76

0.652TH = 76

TH = 76/0.652

TH = 116.56°C

Thus, the temperature of the boiler of the steam engine at the efficiency of 34.8% and waste heat temperature of 76 °C, is determined as 116.56°C.

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