Question

Questions #4, 5, and 6:

Part 1 of 3: Two moles of helium gas initially at 335 K and 0.58 atm are compressed isothermally to 1.44 atm. Find the final volume of the gas. Assume that helium behaves as an ideal gas. The universal gas constant is 8.31451 J/K · mol. Answer in units of m³.

Part 2 of 3: Find the work done by the gas. Answer in units of kJ.

Part 3 of 3: Find the thermal energy transferred. Answer in units of kJ.

Answer 1

For two moles of helium gas initially at 335 K and 0.58 atm are compressed isothermally to 1.44 atm, The solutions are is mathematically given as

1. V2=0.03818 m3
2. W=-5.065KJ
3. Q =5.065 KJ

What is the final volume of the gas?

Generally, the equation for the Ideal gas law  is mathematically given as

PV=nRT

Therefore

V1=2*8.31451*335/(0.58*1.01325*105)

V1=0.09479 m3

Also

V2=V1*(P1/P2)

V2 =0.09479*(0.58/1.44)

V2=0.03818 m3

b)

W=nRTLn(V2/V1)

W=2*8.31451*335*Ln(0.03818/0.09479)

W=-5.065KJ

c)

In conclusion, Heat energy

Q=-W

Q =5.065 KJ

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