For a sample of helium behaves as an ideal gas as it is heated at constant pressure from 293 K to 363 K, the mass of the helium sample is mathematically given as
n= 0.0986 g
Generally, the equation for the ideal gas is mathematically given as
PV=nRT
Therefore
W = P*(V2-V1)
W=nR(T2- T1)
n = W / (R*(T2 - T1) )
n= 4g/mol ∙ 16 J / (8.3145J/molK ∙ (351K - 273K) )
n= 0.0986 g
In conclusion, the mass of the helium sample
n= 0.0986 g
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