Question

6. A spring is originally 1.5 m long. It is stretched so that it is 1.8 m long. The spring constant is 50 N/m.
Find the potential energy stored in the spring.

Answer 1

Answer:

PE = 1/2 K X^2

K = 50 N/m

X = .3 m

PE = 1/2 * 50 * .3^2 = 2.25 Joules