Question

5. What is the potential energy of a spring if the spring constant is 25.0 N/m and it is compressed to .5 m past its resting position?

Answer 1

Explanation:

Given: Required: solution:

k=25N/m PE ? PE= 1/2 × KX²

X= 5m 1/2 × (25)(5)²

= 312.5 J