Question

CHOOSING BRAINLIEST
A counselor determined that 60% of the senior class had taken a precalculus course and that 15% of the senior class had taken both a precalculus course and a statistics course?
What percentage of seniors who took a precalculus course also took a statistics course?

Answer 1

Using conditional probability, it is found that 25% of seniors who took a precalculus course also took a statistics course.

What is Conditional Probability?

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which:

• P(B|A) is the probability of event B happening, given that A happened.

• $P(A \cap B)$ is the probability of both A and B happening.

• P(A) is the probability of A happening.

In this problem, the events are:

• Event A: Senior student took a precalculus course.

• Event B: Senior student took a statistics course.

The probabilities given are $P(A) = 0.6, P(A \cap B) = 0.15$.

The desired probability is P(B|A), hence:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.15}{0.6} = 0.25$

0.25 = 25% of seniors who took a precalculus course also took a statistics course.

More can be learned about conditional probability at https://brainly.com/question/14398287