A) tan
B) tan^2
C) 1
D) -1
![A tan B tan2 C 1 D 1 class=](https://us-static.z-dn.net/files/dc9/7b6c9be49dd01977278e289bb25669d5.png)
Answer:
A) [tex]\tan \theta[/tex]
Step-by-step explanation:
[tex] \frac{\sin \theta}{ \sqrt{1 - { \sin}^{2} \theta } } \\ \\ = \frac{\sin \theta}{ \sqrt{ { \cos}^{2} \theta } } \\ \\= \frac{\sin \theta}{{ { \cos} \theta } } \\ \\ = \tan \theta[/tex]