Answer:
[tex] \fbox{ \sf A) Age of Helen’s brother = N+1} \\ \fbox{ \sf B) Age of Helen’s brother = 13 \: year \: old} \\ \fbox{ \sf C) Age of Helen’s brother = x+1} [/tex]
Step-by-step explanation:
Given:
Helen's age = N year old
Helen's brother = One year older than helen
To find:
a. Write n algebraic expression for the age of Helen’s brother
b. Find her brother’s age if Helen is age 12
C. Find her brothers age If Helen is x years old
Solution:
A)algebraic expression for the age of Helen’s brother = Helen’s age + 1 = N+1
[tex]\fbox{Age of Helen’s brother = N+1}[/tex]
B) if helen is 12 year old then, N = 12
substituting the value of N in above equation,
Age of Helen’s brother = N+1 = 12+1 = 13 y/o
[tex]\fbox{Age of Helen’s brother = \: 13 \: year \: old}[/tex]
C) if helen is x year old then, N = x
substituting the value of N in above equation,
Age of Helen’s brother = N+1 = x+1
[tex]\fbox{Age of Helen’s brother = x+1}[/tex]
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