Question

A toy train is going around a circular track of a radius of 1.2 m as shown on the diagram. The train takes 9 seconds to complete one lap of the circular track.
(a) Calculate the speed of the train

(B) on the diagram draw in the train's velocity and acceleration vectors at B. Label clearly.


(c) For the train to move in a circle like this there
must be a centripetal force acting on it.
Explain how this force is being produced

Answer 1

Explanation:

r=1.2, Period(T) = 9s

a) Speed(V) = ωr

ω = 2 x Pi(3.142) x frequency

frequency = 1/period

therefore; the frequency will be 1/9 = 0.1Hz

Therefore Speed(V) = 2 x 3.142 x 0.1 x 1.2=0.75m/s

C) Centripetal and centrifugal forces are the forces experienced by rotating objects. The centripetal force keeps an object moving in a circle and is always pointed toward the center of that circle. For instance, the gravitational force of the sun is a centripetal force that keeps the Earth orbiting around it. Its direction is always orthogonal to the motion of the body and towards the fixed point of the instantaneous center of curvature of the path.