Answer:
-0.0092
Step-by-step explanation:
sin160°cos110° + sin290°cos340° + tan110°tan160°
(0.34)(-0.34) + (-0.94)(0.94) + (-2.75)(-0.36)
- 0.1156 - 0.8836 + 0.99
-0.0092
I hope this helps!
[tex]\sin 160^{\circ} \cos 110^{\circ} + \sin 290^{\circ} \cos 340^{\circ} + \tan 110^{\circ} \tan 160^{\circ}\\\\=\sin\left(2 \times 90^{\circ} - 20^{\circ} \right) \cos \left(90^{\circ} + 20^{\circ} \right) + \sin \left(3 \times 90^{\circ}+20^{\circ}\right) \cos\left(4 \times 90^{\circ}-20^{\circ \right) + 20^{\circ} \right) + \tan \left( 90^{\circ} +20^{\circ}\right) \tan\left( 2 \times 90^{\circ} - 20^{\circ} \right)\\\\[/tex]
[tex]=-\sin 20^{\circ} \sin 20^{\circ} -\cos 20^{\circ} \cos 20^{\circ}+\cot 20^{\circ} \tan 20^{\circ}\\\\=-\left(\sin^2 20^{\circ} + \cos^2 20^{\circ} \right) + \tan 20^{\circ} \cdot \dfrac 1{\tan 20^{\circ}}\\\\=-1 + 1\\\\=0[/tex]
