Respuesta :
Question :-
- A Cylinder has a Radius of 3 Ft and a Height of 5 Ft . Find the Volume .
Answer :-
- Volume of Cylinder is 141.42 Ft³ .
Explanation :-
As per the provided information in the given question, we have been given that the Radius of the Cylinder is 3 Ft . The Height is given as 5 Ft . And, we have been asked to calculate the Volume of Cylinder .
For calculating the Volume , we will use the Formula :-
[tex] \bigstar \: \: \: \boxed{ \sf{ \: Volume \: _{Cylinder} \: = \: \pi {r}^{2}h \: }} [/tex]
Where ,
- R denotes to Radius
- H denotes to Height
Therefore , by Substituting the given values in the above Formula :-
[tex] \Longrightarrow \: \: \: \sf { Volume \: _{Cylinder} \: = \: \pi {r}^{2}h } [/tex]
[tex] \Longrightarrow \: \: \: \sf { Volume \: _{Cylinder} \: = \: \dfrac {22}{7} \: \times \: ({3})^{2} \: \times \: 5 } \\ [/tex]
[tex] \Longrightarrow \: \: \: \sf { Volume \: _{Cylinder} \: = \: \dfrac {22}{7} \: \times \: 9 \: \times \: 5 } \\ [/tex]
[tex] \Longrightarrow \: \: \: \sf { Volume \: _{Cylinder} \: = \: \dfrac {22\: \times \: 9 \: \times \: 5 }{7}} \\ [/tex]
[tex] \Longrightarrow \: \: \: \sf { Volume \: _{Cylinder} \: = \: \dfrac { \: 990 \: }{7}} \\ [/tex]
[tex] \Longrightarrow \: \: \: \bf { Volume \: _{Cylinder} \: = \: 141.42 } [/tex]
Hence :-
- Volume of Cylinder = 141.42 Ft³ .
[tex] \underline {\rule {180pt}{4pt}} [/tex]
Answer:
Volume of cylinder is 141.3 ft³ ( Taking value of π as 3.14 )
Step-by-step explanation:
Question : -
A cylinder has a radius of 3 ft and a height of 5 ft. Find the volume .
Given : -
- Radius of cylinder = 3 ft
- Height of cylinder = 5 ft
To Find : -
We have to , volume of Cylinder .
Formula Used : -
[tex] \boxed{ \sf{Volume \: of \: Cylinder = \pi r {}^{2} h }}[/tex]
Where ,
- π = 3.14
- r = radius of cylinder
- h = height of cylinder
Solution : -
[tex] \longrightarrow \: \pi r {}^{2} h[/tex]
Now , substituting values of radius and height :
[tex]\longrightarrow \: 3.14 \times (3) {}^{2} \times 5[/tex]
Now , calculating :
[tex] \longrightarrow 3.14 \times 9 \times5 [/tex]
Firstly , multiplying 9 and 5 :
[tex]\longrightarrow \: 3.14 \times 45[/tex]
Atlast , multiplying 3.14 and 45 :
[tex] \longrightarrow \: \bold{ 141.3}[/tex]
[tex] \red{ \boxed{ \rm{Therefore , \: volume \: of \: cylinder \: is \: 141.3 \: ft {}^{3} }}}[/tex]