Question

22. Four years ago, age of X was 3 times Y. Six years from now X will be twice Y. Ages of X and Y
now are:
A.
034 and 14
B.
034 and 13
C.
033 and 14
D.
035 and 14

Answer 1

Answer:

a 34 and 14

Step-by-step explanation:

let present age be x and y

equation 1

x-4=3(y-4)

x=3y-8

equation 2

x+6=2(y+6)

x=2y+6

then

2y+6=3y-6

y=14

x=34