Question

What is the area of a sector of a circle with a radius of 8 inches and formed by a central angle that measures 80 degrees?

Answer 1

$\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta \pi r^2}{360}~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ r=8\\ \theta =80 \end{cases}\implies \begin{array}{llll} A=\cfrac{(80)\pi (8)^2}{360}\implies A=\cfrac{128\pi }{9} \\\\\\ A\approx 44.68~in^2 \end{array}$