Question

WILL CHOOSE BRAINLIEST! The height of a baseball, h (in feet), as a function of time, t (in seconds), is given by the equation h(t)=-16t²+32t+3. find the average velocity (in ft/sec) of the baseball from t=0 to t=1.

Answer 1

Answer:

Given the equation y = -16t^2 + 96t + 3, we know a = -16, b = 96, c = 3.

Let's solve for h in this problem.  

h = -b/2a

h = -(96) / 2(-16)

h = -96 / -32

h = 3 seconds

Now let's add t=3 to our equation:

y = -16t^2 + 96t + 3

y = -16*(3)^2 + 96*(3)+ 3

y = -144 + 288 + 3

We now know that the vertex is (3,147), which means that the ball's maximum height is 147 feet.

Answer 2

Answer:

Step-by-step explanation:

Find the height at   h(0)   and   h(1)

h(0) = 3 ft

h(1) = -16 + 32 + 3 = 19 ft

It takes 1 second to go from 3 feet to 19 feet

  (19-3) ft / 1 sec = 16 ft/sec