Question

what is the angle of elevation of the sun when the shadow of a pole of 18m high is 6√3m long? ( i need step by step explanation pls I'm having a class test tmr pls help)​

Answer 1

Answer:

See diagram below

Step-by-step explanation:

arctan (angle ) = 18 / (6 sqrt3)  = 60 degrees

Answer 2

Step-by-step explanation:

height of pole = 18m = p

length of shadow = 6$\sqrt{3}$ m = b

now,

tan α = p/b

        = 18/6$\sqrt{3}$

        = $\sqrt{3}$

or, tan α = tan 60

           α = 60

Therefore angle of elevation of the sun is 60.