Answer:
[tex]7y=-5x-11[/tex]
Step-by-step explanation:
Since it says the lines are parallel both of their gradients will be same.
so gradient of line 1 = [tex]y=\frac{14-5x}{7}[/tex] = [tex]y=\frac{14}{7}-\frac{5x}{7}[/tex]= [tex]-\frac{5}{7}[/tex]
so equation of line 2 = [tex]y-y_{1}=m(x-x_{1} )[/tex]
= [tex]y-(-3)_{}=\frac{-5}{7} (x-(-2)_{} )[/tex]
= [tex]y +3=-\frac{5}{7}x+\frac{10}{7}[/tex]
= [tex]y =-\frac{5x+10}{7}-3[/tex]
= [tex]7y=-5x-11[/tex]
Step-by-step explanation:
basically a line equation typically looks like
y = ax + b
with a being the slope, and b bent the y-intercept (y value when x = 0).
5x + 7y = 14
7y = -5x + 14
y = -5/7 x + 14/7 = -5/7 x + 2
so, wie know the slope of the original line : -5/7 .
any line parallel to it must have the same slope.
our desired line looks like
y = -5/7 x + b
to get b we use the provided point (-2, -3).
-3 = -5/7 × -2 + b = 10/7 + b
-21/7 = 10/7 + b
-31/7 = b
and the full equation is
y = -5/7 x - 31/7
7y = -5x - 31
5x + 7y = -31
