Question

Find the area of the plane figure :​

Answer 1

Answer:

99.9 $cm^{2}$

Step-by-step explanation:

Given, AB=13 cm, BC=4 cm

AC is the diagonal of parallelogram ABCD.

Also AC=16 cm

We know, △ABC≅△ACD     [S−S−S Congruence]

Also, area of parallelogram ABCD = Area of △ABC + Area of △ACD

                                            = 2 × Area of △ABC

                                            = $2\sqrt{s(s-13)(s-4)(s-15)}$

         $s= \frac{13+15+4}{2}$                 = $2\sqrt{16(16-13)(16-4)(16-15)}$

             = 16                          = 99.9