The number of atoms in 41.7 g of tin is 2.12 × 10²³ atoms
The mass of 2.37 × 10²² atoms of xenon gas is 5.17 grams
Avogadro's number;
Avogadro's number, or Avogadro's constant, is the number of particles found in one mole of a substance.
Therefore,
6.022 × 10²³ atom = 1 mole of Tin(Sn) = 118.71 g
Therefore,
118.71 g = 6.022 × 10²³ atom
41. 7 g = ?
Atoms in 41.7 g of tin = 41.7 × 6.022 × 10²³ / 118.71
Atoms in 41.7 g of tin = 251.1174 × 10²³ / 118.71 =
Atoms in 41.7 g of tin = 2.11538539297 × 10²³
Atoms in 41.7 g of tin = 2.12 × 10²³ atoms
The mass of 2.37 × 10²² atoms of xenon gas can be calculated as follows:
6.022 × 10²³ atom = 131.293 g
2.37 × 10²² atoms = ?
mass of Xenon gas = 2.37 × 10²² × 131.293 / 6.022 × 10²³
mass of Xenon gas = 311.16441 × 10²² / 6.022 × 10²³
mass of Xenon gas = 51.6712736632 × 10⁻¹
mass of Xenon gas = 5.17 grams
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