Question

If a car has an initial speed of +15 meters/second and a constant acceleration of +1 meters/second2, how much distance will it travel in the first 10 seconds after the acceleration begins?

Answer 1

Using kinematic equation:
S = ut + $\frac{a*t ^{2} }{2}$.
S = 15x10 + $\frac{1*(10) ^{2} }{2}$.
S = 200 meters. 
Hence car will travel a distance of 200 meters.
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