Respuesta :
Ф: angle before refraction
β: angle after refraction
Ф > β
sinФ > sinβ
The velocity is directly proportion to the sine of refraction taken from normal so
[tex] \frac{sinФ}{sinβ} [/tex] > 1
[tex] \frac{v1}{v2} [/tex] > 1
v1 > v2
The speed in the medium B is less than it in A
β: angle after refraction
Ф > β
sinФ > sinβ
The velocity is directly proportion to the sine of refraction taken from normal so
[tex] \frac{sinФ}{sinβ} [/tex] > 1
[tex] \frac{v1}{v2} [/tex] > 1
v1 > v2
The speed in the medium B is less than it in A